Contest for White Rabbit

Voodoo
Joined 14/02/2019
Posts 1,845

03:46 PM 23/03/2019

2 3 and 1

[15] UnwantedWarrior
Joined 22/01/2019
Posts 2,447

03:46 PM 23/03/2019

my answer is a number from 0-1,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000

[ivo] ivo
Joined 18/03/2017
Posts 2,566

03:46 PM 23/03/2019

Quote from Winar , 03:45 PM 23/03/2019
Quote from ivo , 03:44 PM 23/03/2019
Quote from Voodoo , 03:43 PM 23/03/2019
Given equations are,

2x² - xy - y² + 3x + 2y - 3 = 0. ...(1)

x² - 3x + 2 = 0. ...(2)

From equation (2),

x² - 3x + 2 = 0
or, x² - 2x - x + 2 = 0
or,. ( x - 2) ( x - 1 ) = 0

So, values of x are

x = 1, 2.

On putting the values of x in equation(1), we get

For x = 1, the value of y is

2(1)² - (1)y - y² + 3(1) + 2y - 3 = 0

- y² + y + 2 = 0
or,
y² - y - 2 = 0

y = (1±3)/2

On taking +ve sign,

y = 2

On -ve sign,

y = -1.

And for x = 2, the value of y is

2(4) - 2y - y² + 3(2) + 2y - 3 = 0

8 - y² + 6 - 3 = 0
or, y² = 11
or, y = ±√11

So, the values of x&y are

x = 1. y = -1, 2.
x = 2. y = ±√11

How i did it: searched it on quora

Hint: you're not mean to find the values of x, y or z.

answer is nothing

The answer is a single, real number.

[15] UnwantedWarrior
Joined 22/01/2019
Posts 2,447

03:46 PM 23/03/2019

Quote from UnwantedWarrior , 03:46 PM 23/03/2019
my answer is a number from 0-1,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000

did i win

[ivo] ivo
Joined 18/03/2017
Posts 2,566

03:47 PM 23/03/2019

Quote from UnwantedWarrior , 03:46 PM 23/03/2019
my answer is a number from 0-1,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000

So many numbers and you're still wrong.

[15] UnwantedWarrior
Joined 22/01/2019
Posts 2,447

03:47 PM 23/03/2019

Quote from ivo , 03:47 PM 23/03/2019
Quote from UnwantedWarrior , 03:46 PM 23/03/2019
my answer is a number from 0-1,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000

So many numbers and you're still wrong.

listen i am not in college

[IV] brick-house
Joined 21/01/2019
Posts 8,331

03:48 PM 23/03/2019

Quote from ivo , 03:47 PM 23/03/2019
Quote from UnwantedWarrior , 03:46 PM 23/03/2019
my answer is a number from 0-1,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000

So many numbers and you're still wrong.

Is it 0?

Winar
Joined 12/08/2018
Posts 7,230

03:48 PM 23/03/2019

Quote from ivo , 03:46 PM 23/03/2019
Quote from Winar , 03:45 PM 23/03/2019
Quote from ivo , 03:44 PM 23/03/2019
Quote from Voodoo , 03:43 PM 23/03/2019
Given equations are,

2x² - xy - y² + 3x + 2y - 3 = 0. ...(1)

x² - 3x + 2 = 0. ...(2)

From equation (2),

x² - 3x + 2 = 0
or, x² - 2x - x + 2 = 0
or,. ( x - 2) ( x - 1 ) = 0

So, values of x are

x = 1, 2.

On putting the values of x in equation(1), we get

For x = 1, the value of y is

2(1)² - (1)y - y² + 3(1) + 2y - 3 = 0

- y² + y + 2 = 0
or,
y² - y - 2 = 0

y = (1±3)/2

On taking +ve sign,

y = 2

On -ve sign,

y = -1.

And for x = 2, the value of y is

2(4) - 2y - y² + 3(2) + 2y - 3 = 0

8 - y² + 6 - 3 = 0
or, y² = 11
or, y = ±√11

So, the values of x&y are

x = 1. y = -1, 2.
x = 2. y = ±√11

How i did it: searched it on quora

Hint: you're not mean to find the values of x, y or z.

answer is nothing

The answer is a single, real number.

uhhhhhhhhhhhhhhhhh 9?

[vape] no_u
Joined 29/11/2018
Posts 615

03:48 PM 23/03/2019

tbh the answer is real number

[Deleted809]
Joined 16/04/2017
Posts 1,828

03:48 PM 23/03/2019

insert answer here